In fact, it's really easy to do once you recall the derivative of inverse tangent.
looks familiar doesn't it? All I really did was multiply the derivative of arctan(e^x) with the function itself. And I love how no one was able to figure it out.
Solution
We just have to follow the standard procedure for u-substitution and we're good.
When we differentiate both sides it looks as follows. Notice how it looks almost exactly like the function we started out with.
We now have all the ingredients for u-substitution.
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